Mathematically: What is SUSY? - Physics Stack Exchange
Wikipedia says: In particle physics, supersymmetry (often abbreviated SUSY) is a symmetry that relates elementary particles of one spin to other particles that differ by half a unit of spin and are
cal N}=4$ supersymmetric yang-mills theory and S-duality
What is the action for $ {\cal N}=4$ SUSY Yang-Mills and what is the physics of the various terms in the action? B. Give a simple explanation for the origin of Montonen-Olive duality in this theory.
Confusion about commutator between $R$-symmetry and …
Nov 2, 2024 · This is what it means to be linear operator. A map from a vector space to another (in this case the same vector space). The "definition" of R symmetry acting on supercharges …
Difference between $\\mathcal{N}=2$ and $\\mathcal{N}=(1,1)
Jul 30, 2023 · I think I figured out the meaning of this after some research so, I am posting an answer to my own question. The answer is there is nothing called $\mathcal {N}= (1,1)$ …
SUSY and van der Waerden spinor notation - Physics Stack Exchange
Jul 22, 2021 · 2 I am currently trying to read into SUSY and I am running into trouble with the van der Waerden spinor notation for Weyl spinors. I am looking for resources that construct and …
Spontaneous breaking of supersymmetry - Physics Stack Exchange
Jun 11, 2019 · Thus, if you have some non-trovial action of the susy generator as in (2), then the state will not be invariant under finite group transformations (but rather covariant). Also, note …
What if the LHC doesn't see SUSY? - Physics Stack Exchange
Obviously, if SUSY is there at the LHC scale, the LHC will eventually be discovering fireworks of new effects (SUSY is also the most attractive realistic possibility for the experimenters) - all the …
How does one determine the $R$-symmetry group?
Jun 13, 2020 · Properties of R-symmetry group depends on spinor structure: Here M means Maiorana spinors, MW - Maiorana-Weyl, S- symplectic. Spinor structure depends on …
Why is the R-symmetry in $\\mathcal{N}=4$ $SU(4)$ and not …
But $\mathcal {N}=4$ is a SCFT, and the R-charge appears in the SUSY algebra on the r.h.s. of the anticommutators $\ {S,Q\}$ and cannot be anomalous without breaking SCFT.
How can string theory work without supersymmetry?
If you spend some time looking in detail at the arguments that string theory requires supersymmetry, you'll find that they are not watertight. (How could they be, since we still can't …